Rewrite \(y = {x^2} - 6x + 11\) in the form \(y = a{(x - b)^2} + c\). In this case \(a = 1\) as the coefficient of \({x^2}\) is \(1\). To get the number inside the bracket, we half the coefficient of ...
Rewrite \(y = {x^2} - 6x + 11\) in the form \(y = {(x - b)^2} + c\). To get \(b\) (the number inside the bracket), halve the coefficient (number in front) of the second term in the original equation.
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