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  1. Define collinear vectors. - Toppr

    Two vectors are collinear if they are parallel to the same line, irrespective of their magnitude and direction.

  2. For what value of x are the points A(-3, 12), B(7, 6) and C(x, 9 ...

    Click here:point_up_2:to get an answer to your question :writing_hand:for what value of x are the points a3 12 b7 6 and cx 9

  3. Define collinear points. - Toppr

    Collinear points are points that lie on the same line. The word 'collinear' breaks down into the prefix 'co-' and the word 'linear.' 'Co-' indicates togetherness, as in coworker or cooperate. 'Linear' refers to a …

  4. Let a, b and c be three non-zero vectors, no two of which are collinear ...

    Let a,b and c be three non-zero vectors, no two of which are collinear. If the vector a+2b is collinear with c, and b +3c is collinear with a, then a+2b+6c is equal to

  5. Show that the points (1,-1), (5,2) and (9,5) are collinear. - Toppr

    Click here:point_up_2:to get an answer to your question :writing_hand:show that the points 11 52 and 95 are collinear

  6. Determine the points (1, 5) , (2, 3) and (-2, -11) are collinear , by ...

    Determine, by distance formula, whether the points (- 6, - 2), (2,3 and (10,8) are collinear. View Solution

  7. The vectors vec a and vec b are non-collinear. Value of x ,for the ...

    ¯a and ¯b are non collinear vectors. If ¯c = (x−2)¯a +¯b and ¯d = (2x+1)¯a −¯b are collinear vectors, then find the value of x.

  8. By using the concept of equation of a line, prove that the ... - Toppr

    Using the vector equation of the straight line passing through two points, prove that the points whose vectors are a,b and (3a−2b) are collinear.

  9. There are 10 points in a plane, no three of which are in the ... - Toppr

    We know that joining of any 2 points give a line. Thus the number of lines obtained from 10 points, when no 3 of which are collinear = 10C2 = 45

  10. For what value of K are the points (k , 2 -2k), (-k - Toppr

    Using determinants, find the value of k so that the points (k, 2 − 2 k), (−k + 1, 2k) and (−4 − k, 6 − 2k) may be collinear.